Finding the PDF from a Given CDF
The cumulative distribution function (CDF) is defined as:
\( F(x) = 1 – e^{-2x} \) for \( x \geq 0 \)
\( F(x) = 0 \) for \( x < 0 \)
To find the probability density function (PDF), we take the derivative of the CDF:
\( f(x) = 2e^{-2x} \) for \( x \geq 0 \)
\( f(x) = 0 \) for \( x < 0 \)
Conclusion: The PDF is \( f(x) = 2e^{-2x} \) for \( x \geq 0 \), and \( f(x) = 0 \) for \( x < 0 \). This function describes the density of the probability distribution for the given range of \( x \).
Value of the PDF for x > 2
Given the probability density function (PDF):
f(x) = 2e⁻²ˣ for x ≥ 0
f(x) = 0 for x < 0
We can find the value of the PDF for x > 2 by substituting x = 2 into the expression:
f(x) = 2e⁻⁴ ≈ 0.0366 for x > 2
Conclusion: The value of the PDF for x > 2 is approximately 0.0366. This value represents the density of the probability distribution for x > 2.