Efficient Calculation of Partial Derivatives ∂f/∂x and ∂f/∂y
| For ∂f/∂x: | |
| ∂/∂x(2x + 2y) | = Start with the original function |
| = ∂/∂x(2x) + ∂/∂x(2y) | = Apply the sum rule for differentiation |
| = 2 ∂/∂x(x) + 0 | = Partial differentiate each term |
| = 2 × 1 + 0 | = Evaluate the partial derivatives |
| = 2 | = Simplify |
| For ∂f/∂y: | |
| ∂/∂y(2x + 2y) | = Start with the original function |
| = ∂/∂y(2x) + ∂/∂y(2y) | = Apply the sum rule for differentiation |
| = 0 + 2 ∂/∂y(y) | = Partial differentiate each term |
| = 0 + 2 × 1 | = Evaluate the partial derivatives |
| = 2 | = Simplify |
Detailed Calculation of Partial Derivatives ∂f/∂x and ∂f/∂y for f(x, y) = 4x² + 2y
| For ∂f/∂x: | |
| ∂/∂x(4x² + 2y) | = Start with the original function |
| = ∂/∂x(4x²) + ∂/∂x(2y) | = Apply the sum rule for differentiation |
| = 2 * 4 * x¹ | = Apply the power rule on 4x², knowing 2y is constant with respect to x |
| = 8 * x | = Simplify, 2 * 4 = 8 |
| = 8x | = Write in simplified form |
| For ∂f/∂y: | |
| ∂/∂y(4x² + 2y) | = Start with the original function |
| = 0 + ∂/∂y(2y) | = 4x² is constant with respect to y |
| = 0 + 2 | = Differentiate 2y with respect to y |
| = 2 | = Write in simplified form |
Detailed Calculation of Partial Derivatives ∂f/∂x and ∂f/∂y for \( f(x, y) = 4x² + 2y³ + 4 \)
| For ∂f/∂x: | |
| ∂/∂x(4x² + 2y³ + 4) | = Start with the original function |
| = ∂/∂x(4x²) + ∂/∂x(2y³) + ∂/∂x(4) | = Apply the sum rule for differentiation |
| = 2 * 4 * x¹ + 0 + 0 | = Apply the power rule on 4x²; 2y³ and 4 are constants with respect to x |
| = 8 * x | = Simplify, 2 * 4 = 8 |
| = 8x | = Write in simplified form |
| For ∂f/∂y: | |
| ∂/∂y(4x² + 2y³ + 4) | = Start with the original function |
| = 0 + ∂/∂y(2y³) + 0 | = 4x² and 4 are constants with respect to y |
| = 0 + 3 * 2 * y² | = Differentiate 2y³ with respect to y |
| = 6 * y² | = Simplify, 3 * 2 = 6 |
| = 6y² | = Write in simplified form |
Master the Concept of Partial Derivatives with f(x, y) = x³y – x + 4
Unlocking the Secrets of ∂f/∂x:
| ∂/∂x(x³y – x + 4) | Start by writing down the function f(x, y) and indicating we want the partial derivative with respect to x. |
| = ∂/∂x(x³y) + ∂/∂x(-x) + ∂/∂x(4) | Apply the linearity property of derivatives to break down into simpler parts. |
| = y * 3x² – 1 | Perform the differentiation: the derivative of x³y with respect to x is y * 3x², and the derivative of -x is -1. |
| = 3x²y – 1 | Simplify the expression to get the final result for ∂f/∂x. |
Demystifying the Partial Derivative ∂f/∂y:
| ∂/∂y(x³y – x + 4) | Start by writing down the function f(x, y) and indicating we want the partial derivative with respect to y. |
| = ∂/∂y(x³y) | Since x and 4 are constants with respect to y, their derivatives become zero, leaving us with only ∂/∂y(x³y). |
| = x³ | Perform the differentiation: the derivative of x³y with respect to y is simply x³. |
Unlock the Complexity of Partial Derivatives with f(x, y) = x/y
Dive Into the Mysteries of ∂f/∂x:
| ∂(x/y)/∂x | Start by indicating we want to find the partial derivative of f(x, y) = x/y with respect to x. |
| ∂(x * y⁻¹)/∂x | Express x/y as x * y⁻¹ for easier differentiation. |
| y⁻¹ | Perform the differentiation. The derivative of x with respect to x is 1. Multiply by y⁻¹ to get y⁻¹. |
| 1/y | Simplify y⁻¹ to 1/y, achieving the final result for ∂f/∂x. |
Discover the Partial Derivative ∂f/∂y:
| ∂(x/y)/∂y | Start by indicating we want to find the partial derivative of f(x, y) = x/y with respect to y. |
| ∂(x * y⁻¹)/∂y | Express x/y as x * y⁻¹ for easier differentiation. |
| -x * y⁻² | Perform the differentiation. The derivative of y⁻¹ with respect to y is -y⁻². Multiply by x to get -x * y⁻². |
| -x/y² | Simplify -x * y⁻² to -x/y², achieving the final result for ∂f/∂y. |
Dive Deep into Partial Derivatives: A Detailed Walkthrough of \( f(x, y) = xy \)
Understanding ∂f/∂x:
| ∂/∂x(xy) | Initial expression for partial derivative with respect to x. |
| = y ∂/∂x(x) | Apply the differentiation rules, treating y as a constant. |
| = y × 1 | Derivative of x with respect to x is 1. |
| = y | Simplifying, we get y. |
Understanding ∂f/∂y:
| ∂/∂y(xy) | Initial expression for partial derivative with respect to y. |
| = x ∂/∂y(y) | Apply the differentiation rules, treating x as a constant. |
| = x × 1 | Derivative of y with respect to y is 1. |
| = x | Simplifying, we get x. |
