This guide explains how to determine the convergence or divergence of the infinite geometric series 5 divided by 3 to the power of n, from n=0 to infinity. The series is identified as a geometric series with a common ratio of 1/3, which is less than 1. Therefore, the series converges. Using the formula for the sum of an infinite geometric series, the sum is calculated to be 7.5

ConvergentGeometricSeriesExamplePart2

 

Convergence or Divergence of \(\sum_{n=0}^{\infty} \frac{5}{3^n}\)

This guide explains how to determine if the mathematical series \(\sum_{n=0}^{\infty} \frac{5}{3^n}\) converges or diverges using the formula for an infinite geometric series.

Step 1: Identify the Series Type

The series is a geometric series with \( a = 5 \) and \( r = \frac{1}{3} \).

Step 2: Check the Common Ratio

We need to check if the common ratio \( |r| < 1 \) for the series to converge.

Output: \( |r| = |\frac{1}{3}| = \frac{1}{3} < 1 \)

Step 3: Apply the Geometric Series Formula

Since \( |r| < 1 \), the series converges and its sum can be found using the formula \( S = \frac{a}{1 - r} \).

Output: \( S = \frac{5}{1 – \frac{1}{3}} = \frac{5}{\frac{2}{3}} = \frac{15}{2} = 7.5 \)

Conclusion

By using the formula for an infinite geometric series, we can conclude that the series \(\sum_{n=0}^{\infty} \frac{5}{3^n}\) converges and its sum is \( 7.5 \).