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🔥 Unleash the Power of Math! Dive deep into the mesmerizing world of polynomial factoring! From x³ + 7x² + 10x to 2x⁴ + 8x³ + 6x², learn how to effortlessly break down complex expressions into simpler forms. 👩‍🎓👨‍🎓 Become a Factoring Pro Today! 🌟

Step 1: Look at the expression x³ + 7x² + 10x.

You have three terms: x³, 7x², and 10x.

The first question to ask is: What is common among all these terms?

Answer: Each term has an x:

  • x³ has x × x × x
  • 7x² has x × x
  • 10x has just one x

So we can say that x is a part of every term.

That’s why we take x out of each term and write it as x(x² + 7x + 10).

By doing this, we’re simplifying the expression. We’re breaking it down into parts that are easier to manage. That’s the whole idea behind “factoring.”

Step 2: Now we look at x² + 7x + 10 that’s inside the brackets.

We want to factor this quadratic expression. To do this, we look for two numbers that:

  • Add up to the coefficient of x, which is 7, and
  • Multiply to the constant term, which is 10.

The numbers that fit these conditions are 5 and 2 because 5 + 2 = 7 and 5 × 2 = 10.

So, we can rewrite x² + 7x + 10 as (x + 5)(x + 2).

Step 3: Putting it all together, we have x(x + 5)(x + 2).

And there you have it! You’ve successfully factored the expression x³ + 7x² + 10x into x(x + 5)(x + 2).

<div>
  <p>Step 1: Look at the expression x³ + 7x² + 10x.</p>
  <p>You have three terms: x³, 7x², and 10x.</p>
  <p>The first question to ask is: What is common among all these terms?</p>
  <p>Answer: Each term has an x:</p>
  <ul>
    <li>x³ has x × x × x</li>
    <li>7x² has x × x</li>
    <li>10x has just one x</li>
  </ul>
  <p>So we can say that x is a part of every term.</p>
  <p>That's why we take x out of each term and write it as x(x² + 7x + 10).</p>
  <p>By doing this, we're simplifying the expression. We're breaking it down into parts that are easier to manage. That's the whole idea behind "factoring."</p>

  <p>Step 2: Now we look at x² + 7x + 10 that's inside the brackets.</p>
  <p>We want to factor this quadratic expression. To do this, we look for two numbers that:</p>
  <ul>
    <li>Add up to the coefficient of x, which is 7, and</li>
    <li>Multiply to the constant term, which is 10.</li>
  </ul>
  <p>The numbers that fit these conditions are 5 and 2 because 5 + 2 = 7 and 5 × 2 = 10.</p>
  <p>So, we can rewrite x² + 7x + 10 as (x + 5)(x + 2).</p>

  <p>Step 3: Putting it all together, we have x(x + 5)(x + 2).</p>
  <p>And there you have it! You've successfully factored the expression x³ + 7x² + 10x into x(x + 5)(x + 2).</p>
</div>

 

Example: Factoring 2x⁴ + 8x³ + 6x²

Step 1: Examine the expression 2x⁴ + 8x³ + 6x².

First, let’s identify what is common among all the terms.

Every term contains x and an even number as a coefficient:

  • 2x⁴ has 2 and x⁴
  • 8x³ has 8 and x³
  • 6x² has 6 and x²

The greatest common factor for the coefficients (2, 8, 6) is 2, and each term has at least x².

So, we can factor out 2x² from each term, resulting in 2x²(x² + 4x + 3).

Step 2: Focus on the x² + 4x + 3 inside the brackets.

We aim to factor this quadratic expression by looking for two numbers that:

  • Add up to the coefficient of x, which is 4.
  • Multiply to the constant term 3.

The numbers that meet these conditions are 3 and 1, as 3 + 1 = 4 and 3 × 1 = 3.

So we rewrite x² + 4x + 3 as (x + 3)(x + 1).

Step 3: Combine all the factors.

We now have 2x²(x + 3)(x + 1) as the fully factored expression.

Congratulations! You’ve successfully factored the expression 2x⁴ + 8x³ + 6x² into 2x²(x + 3)(x + 1).



Example: Factoring -3x⁴ – 9x³ + 12x²

Step 1: Examine the expression -3x⁴ – 9x³ + 12x².

First, let’s find what is common among all the terms.

All terms contain x and coefficients that are multiples of 3:

  • -3x⁴ has -3 and x⁴
  • -9x³ has -9 and x³
  • 12x² has 12 and x²

The greatest common factor for the coefficients (-3, -9, 12) is 3, and each term has at least x².

We can factor out -3x² from each term, resulting in -3x²(x² + 3x – 4).

Step 2: Focus on the x² + 3x – 4 inside the brackets.

We aim to factor this quadratic expression by looking for two numbers that:

  • Add up to the coefficient of x, which is 3.
  • Multiply to the constant term -4.

The numbers meeting these conditions are 4 and -1, as 4 + (-1) = 3 and 4 × (-1) = -4.

So we rewrite x² + 3x – 4 as (x + 4)(x – 1).

Step 3: Combine all the factors.

We now have -3x²(x + 4)(x – 1) as the fully factored expression.

Congratulations! You’ve successfully factored the expression -3x⁴ – 9x³ + 12x² into -3x²(x + 4)(x – 1).

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