Unlock the Paradox: Why the Limit of |x-1|/(x-1) Vanishes

Final Result: Does the Limit of |x-1|/(x-1) as x Approaches 1 Exist?

The limit does not exist. Below is the complete step-by-step explanation:

  • Case for x > 1: In this case, |x – 1| = x – 1. Therefore, the limit becomes lim(x → 1) (x – 1)/(x – 1) which simplifies to 1.
  • Case for x < 1: Here, |x - 1| = -(x - 1). So the limit becomes lim(x → 1) -(x - 1)/(x - 1) which simplifies to -1.
  • Graph Analysis: The graph consists of two separate pieces, one for x > 1 and another for x < 1. Additionally, the graph has holes at the points (1, 1) and (1, -1), signifying that the function is undefined at x = 1.

Since the limit approaches different values for x > 1 and x < 1, and the function is undefined at x = 1, the overall limit as x approaches 1 does not exist.

Behavior of |x-1|/(x-1) as x Approaches 1 from the RHS

x |x-1|/(x-1)
1.1 1
1.01 1
1.001 1
1.0001 1
1.00001 1

The table shows that as x gets closer to 1 from the right-hand side, the value of |x-1|/(x-1) approaches 1.

Behavior of |x-1|/(x-1) as x Approaches 1 from the LHS

x Substituted Fraction (|x-1|/(x-1)) Result of |x-1|/(x-1)
0.9 |0.9-1|/(0.9-1) -1
0.99 |0.99-1|/(0.99-1) -1
0.999 |0.999-1|/(0.999-1) -1
0.9999 |0.9999-1|/(0.9999-1) -1
0.99999 |0.99999-1|/(0.99999-1) -1

The table shows that as x gets closer to 1 from the left-hand side, the value of |x-1|/(x-1) approaches -1.

Domain of the Function |x – 1|/(x – 1)

  • Interval Notation: (-∞, 1) ∪ (1, ∞)
  • Set-Builder Notation: { x ∈ R : x ≠ 1 }
  • In Words: All real numbers except x = 1